Question 80194: n-5/6n-6 = 1/9 - n-3/4n-4
I tried to my best to type the fractions so I hope this makes sense. Can you help me solve this? Found 2 solutions by stanbon, Edwin McCravy:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! [(n-5)/(6n-6)] = 1/9 -[(n-3)/(4n-4)]
[(n-5)/(6(n-1))] = 1/9 -[(n-3)/(4(n-1)]
The least common multiple is (36(n-1))
Multiply thru by the lcm to get:
[6(n-5)] = 4(n-1) - [9(n-3)]
6n-30-= 4n-4 -9n+27
6n-30 = -5n+23
11n=53
n=53/11
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Cheers,
Stan H.
I tried to my best to type the fractions so I hope this
makes sense. Can you help me solve this?
The LCD of all the denominators is
So put the LCD over 1 = -
On the left side you can cancel the 6 into the 36 and
end up with
= -
In the first term on the right you can cancel the 9
into the 36 and end up with
= -
In the last term on the right you can cancel both the 4
into the 36 and the (n-1)'s and now you have just
= -
Remove the parentheses by distributing:
= -
Edwin
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