SOLUTION: the largest of three consecutive numbers is n. the square of this number exceeds the sum of the other two numbers by 38. find the three numbers.

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: the largest of three consecutive numbers is n. the square of this number exceeds the sum of the other two numbers by 38. find the three numbers.       Log On


   

Question 800497: the largest of three consecutive numbers is n. the square of this number exceeds the sum of the other two numbers by 38. find the three numbers.
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
If n is the largest
then( n-1) & (n-2) are the preceding numbers
n^2=(n-1)+(n-2)+38
n^2=2n-3+38
n^2=2n+35
n^2-2n-35=0
n^2-7n+5n-35=0
n(n-7)+5(n-7)=0
(n-7)(n+5)=0
n= 7 OR -5
7,6,5
OR
-5,-6,-7