SOLUTION: I need serious help pleasee~! -6 2/3 x^2 + 1 1/3 x = 2/3 A x = (-1 +- 10i)/3 Bx = (-1 +- 3i)/10 Cx = (1 +- 3i)/-10 Dx = (-1 +- 3i)/-10 E x = (-1 +- 10i)/-3 F x = (

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: I need serious help pleasee~! -6 2/3 x^2 + 1 1/3 x = 2/3 A x = (-1 +- 10i)/3 Bx = (-1 +- 3i)/10 Cx = (1 +- 3i)/-10 Dx = (-1 +- 3i)/-10 E x = (-1 +- 10i)/-3 F x = (      Log On


   



Question 791361: I need serious help pleasee~!
-6 2/3 x^2 + 1 1/3 x = 2/3
A x = (-1 +- 10i)/3
Bx = (-1 +- 3i)/10
Cx = (1 +- 3i)/-10
Dx = (-1 +- 3i)/-10
E x = (-1 +- 10i)/-3
F x = (2 +- 3i)/6

-57 3/5 x^2 + 3 3/5 x = -39 3/5 x^2 - 7 1/5 x + 14 2/5
A x = {2 +- i[SQRT(75)}/10
Bx = {3 +- i[SQRT(71)]}/-10
Cx = {-3 +- i[SQRT(57)]}/7
Dx = {-3 +- i[SQRT(71)]}/-10
E x = {-2 +- i[SQRT(75)]}/-7
F x = {2 +- i[SQRT(39)]}/14

-6 2/5 x^2 + 7 1/5 x - 3 1/5 = 0
A x = {-2 +- i[SQRT(13)]}/2
Bx = {-6 +- i[SQRT(47)]}/16
Cx = {9 +- i[SQRT(21)]}/-2
Dx = {7 +- i[SQRT(126)]}/-2
E x = {-9 +- i[SQRT(47)]}/-16
F x = {2 +- i[SQRT(126)]}/-6
*

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


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John

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