SOLUTION: How do I figure out the standard form of a quadratic equation? y = -X^2 +2X + 13 I got -(X-2)^2 + 15 ....but that is wrong..? Help me find out what I am doing wrong? Thanks

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: How do I figure out the standard form of a quadratic equation? y = -X^2 +2X + 13 I got -(X-2)^2 + 15 ....but that is wrong..? Help me find out what I am doing wrong? Thanks      Log On


   

Question 789474: How do I figure out the standard form of a quadratic equation?
y = -X^2 +2X + 13
I got -(X-2)^2 + 15 ....but that is wrong..?
Help me find out what I am doing wrong? Thanks!

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
y = -X^2 +2X + 13
Note:: That is already in standard form.
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Maybe you want it in intercept form::
x^2 -2x = 13-y
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x^2 -2x + 1 = 14-y
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(x+1)^2 = -(y-14)
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Cheers,
Stan H.