SOLUTION: how to derived quadratic equation?

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Question 779607: how to derived quadratic equation?
Answer by jsmallt9(3758) About Me  (Show Source):
You can put this solution on YOUR website!
I assume you mean the quadratic formula.

To derive the quadratic formula you take the standard form for a quadratic equation:
ax%5E2%2Bbx%2Bc=0
and then solve for x by "completing the square" and using square roots. I hope you have learned about completing the square because it is too complicated to explain here. The normal procedure is to:
  1. Move the constant term to the other side of the equation (to get it "out of the way").
  2. If the leading coefficient, "a", is not a 1 then either factor it out or divide both sides by it.
  3. Find half of the coefficient of x.
  4. Add the square of the half (from the previous step) to each side.
  5. Rewrite the side with the x%5E2 as a binomial square (in the form: (x + "the half")^2)
Let's see this in action:
ax%5E2%2Bbx%2Bc=0
1. Get the constant term "out of the way" (by subtracting "c"):
ax%5E2%2Bbx=-c
2. With a quadratic equation (only one squared term) we can divide both sides by "a":
%28ax%5E2%2Bbx%29%2Fa=%28-c%29%2Fa
which simplifies:
x%5E2%2B%28b%2Fa%29x=%28-c%29%2Fa
3. Find half of the coefficient of x. Half of b/a would be:
%281%2F2%29%2A%28b%2Fa%29+=+b%2F%282a%29
4. Add the square of the half to both sides. Squaring b%2F%282a%29 gives us b%5E2%2F%284a%5E2%29. Adding this to each side:
x%5E2%2B%28b%2Fa%29x%2Bb%5E2%2F%284a%5E2%29=b%5E2%2F%284a%5E2%29%2B%28-c%29%2Fa
5. Rewrite as a binomial square.
%28x%2Bb%2F2a%29%5E2+=+b%5E2%2F%284a%5E2%29%2B%28-c%29%2Fa

Now that we have completed the square we can solve for x. We start with the square root of each side (remembering the positive and negative square roots by using the "plus or minus" sign):
x%2Bb%2F2a = +sqrt%28b%5E2%2F%284a%5E2%29%2B%28-c%29%2Fa%29
Adding %28-b%29%2F2a we get:
x+=+%28-b%29%2F2a+%2B-+sqrt%28b%5E2%2F%284a%5E2%29%2B%28-c%29%2Fa%29

We have solved for x. But our equation does not look like the normal quadratic formula. So we will use some algebra to simplify and rearrange the right side so it looks right. First we will get common denominators in the square root so we can combine the terms:
x+=+%28-b%29%2F2a+%2B-+sqrt%28b%5E2%2F%284a%5E2%29%2B%28-4ac%29%2F%284a%5E2%29%29
Combining:
x+=+%28-b%29%2F2a+%2B-+sqrt%28%28b%5E2-4ac%29%2F%284a%5E2%29%29
Next we can use a property of radicals to make the square root of the fraction a fraction of square roots:
x+=+%28-b%29%2F2a+%2B-+sqrt%28b%5E2-4ac%29%2Fsqrt%284a%5E2%29%29
The square root in the denominator is a perfect square:
x+=+%28-b%29%2F2a+%2B-+sqrt%28b%5E2-4ac%29%2F2a
The two remaining fractions have the same denominator so we can combine them:
x+=+%28-b+%2B-+sqrt%28b%5E2-4ac%29%29%2F2a
which is the "normal" quadratic formula.