SOLUTION: I have worked this problem a few times and have gotten it incorrect / Thanks for your assistance The length of a rectangle is 6 cm greater than the width. The area is 432cm^2.

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: I have worked this problem a few times and have gotten it incorrect / Thanks for your assistance The length of a rectangle is 6 cm greater than the width. The area is 432cm^2.      Log On


   

Question 779252: I have worked this problem a few times and have gotten it incorrect / Thanks for your assistance

The length of a rectangle is 6 cm greater than the width. The area is 432cm^2. Find the length and the width.
Found 2 solutions by Alan3354, MathTherapy:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
The length of a rectangle is 6 cm greater than the width. The area is 432cm^2. Find the length and the width.
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Factor 432 into pairs, find a pair that differ by 6.
1*432 doesn't work
2*216 doesn't work
3*144 doesn't work (both numbers have to be even)
etc

Answer by MathTherapy(10551) About Me  (Show Source):
You can put this solution on YOUR website!

I have worked this problem a few times and have gotten it incorrect / Thanks for your assistance

Don't you think it'd be best to show what you've done that has resulted in a wrong answer?