SOLUTION: If the product is 48. Find the two consecutive factors and write them as an algebraic expression

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Question 773008: If the product is 48. Find the two consecutive factors and write them as an algebraic expression
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
"Consecutive factors"?
n and n+1 as factors?

n(n+1)=48
n^2+n=48
n^2+n-48=0
Check discriminant: %281%5E2-4%2A%28-48%29%29%3C%3E0
n will be nonwhole, but irrational.
Did you leave something off the problem?
Maybe xy=48 for some two whole number factors x and y.
These are your only positive possibilities to get product 48:
1%2A48
2%2A24
3%2A12
6%2A8________This might be what you want, if consecutive EVEN integers.