SOLUTION: A stone is thrown upward from a bridge. the stone's height in feet, above the water t seconds after the stone is thrown is a function given by the equation S(t)=-16t^2+32t+256.

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: A stone is thrown upward from a bridge. the stone's height in feet, above the water t seconds after the stone is thrown is a function given by the equation S(t)=-16t^2+32t+256.       Log On


   

Question 771179: A stone is thrown upward from a bridge. the stone's height in feet, above the water t seconds after the stone is thrown is a function given by the equation S(t)=-16t^2+32t+256. Find the maximum height of the stone
Answer by oscargut(2103) About Me  (Show Source):
You can put this solution on YOUR website!
Maximum is at t = -32/2(-16) = 1
If t =1 S(1)= 272
Then maximum height is 272 feet
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