SOLUTION: What is the vertex of f(x)=4x^2-32x+67?

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Question 771137: What is the vertex of f(x)=4x^2-32x+67?
Answer by tommyt3rd(5050) About Me  (Show Source):
You can put this solution on YOUR website!
x%5Bmin%5D=-b%2F%282a%29=-%28-32%29%2F%282%2A4%29=4
y=4(4)^2-32*4+67=3
vertex: (4,3)
:)