SOLUTION: Can someone help me with this? I need to Find the minimum y-value on a graph of y=f(x) F(x)=x^2+8x-1 What is the minimum y-value? Y=

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Can someone help me with this? I need to Find the minimum y-value on a graph of y=f(x) F(x)=x^2+8x-1 What is the minimum y-value? Y=       Log On


   

Question 764779: Can someone help me with this? I need to Find the minimum y-value on a graph of y=f(x)
F(x)=x^2+8x-1
What is the minimum y-value? Y=
Found 2 solutions by dkrall, rothauserc:
Answer by dkrall(2) About Me  (Show Source):
You can put this solution on YOUR website!
you need to convert it to vertex form: y=a(x-h)^2+k, which is y=(x+4)^2-17
Vertex is (-4,-17), so the minimum y-value is -17

Answer by rothauserc(4718) About Me  (Show Source):
You can put this solution on YOUR website!
Let's look at the graph of F(x)=x^2+8x-1
+graph%28+300%2C+200%2C+-10%2C+10%2C+-18%2C+18%2C+x%5E2%2B8x-1%29+
The minimum y-value looks to be -17