SOLUTION: Please help me solve this question. Show that the real solution of the equation ax2+bx+c=0 are the negative of the real solution of the equation ax2-bx+c=0. Assume that b2-4ac &

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Please help me solve this question. Show that the real solution of the equation ax2+bx+c=0 are the negative of the real solution of the equation ax2-bx+c=0. Assume that b2-4ac &      Log On


   

Question 750837: Please help me solve this question.
Show that the real solution of the equation ax2+bx+c=0 are the negative of the real solution of the equation ax2-bx+c=0. Assume that b2-4ac ≥ 0.
Thank you
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Show that the real solution of the equation ax2+bx+c=0 are the negative of the real solution of the equation ax2-bx+c=0. Assume that b2-4ac ≥ 0.
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Use the Quadratic Formula:
ax^2 + bx + c = 0
has solutions: x = [-b+-sqrt(b^2-4ac)]/(2a)
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ax^2-bx + c = 0
has solutions: x = [b +- sqrt(b^2-4ac)]/(2a)
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[-b+-sqrt(b^2-4ac)]/2a ? [b +- sqrt(b^2-4ac)]/(2a)
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-b/(2a) ? b/(2a)
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-b/(2a) is the negative of b/(2a)
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Cheers,
Stan H.