SOLUTION: Please help me with this problem. Thank you!! 2t^2+7t=4 Thank you!!!

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Question 74972: Please help me with this problem. Thank you!!
2t^2+7t=4
Thank you!!!
Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
2t%5E2%2B7t=4 set = to 0
2t%5E2%2B7t-4=4-4
2t%5E2%2B7t-4=0 Factor however you know how, I'm using grouping or ac method.
2t^2+__t ___t-4=0
Fill in the blanks with two numbers that multiply to give you the product of the first and last coefficients (2*-4=-8), but add to give you the middle coefficient (7). 8*-1=-8 and 8+(-1)=7
2t%5E2%2B8t-1t-4=0 Factor the GCF out of the first two terms and the last two terms:
2t%28t%2B4%29-1%28t%2B4%29=0 factor out (t+4)
%28t%2B4%29%282t-1%29=0 set each parentheses=0 and solve for t.
t+4=0 or 2t-1=0
t+4-4=0-4 or 2t-1+1=0+1
t=-4 or 2t=1
t=-4 or 2t/2=1/2
t=-4 or t=1/2
Check by letting t=-4 and t=1/2 and see if both sides equal.
for t=-4
2%28-4%29%5E2%2B7%28-4%29=4
2%2816%29-28=4
32-28=4
4=4 This one works.
for t=1/2
2%281%2F2%29%5E2%2B7%281%2F2%29=4
2%281%2F4%29%2B7%281%2F2%29=4
2%2F4%2B7%2F2=4
1%2F2%2B7%2F2=4
%281%2B7%29%2F2=4
8%2F2=4
4=4 This one works too.
Happy Calculating!!!!