Question 748235: This doesn't make sense...Someone help me please!The equation is:
r^3=2r^2+15r Found 2 solutions by lynnlo, tinbar:Answer by lynnlo(4176) (Show Source):
You can put this solution on YOUR website! r^3=2r^2+15r
r^3 - 2r^2 - 15r = 0
r(r^2 - 2r - 15) = 0
Therefore r = 0, is one solution and whenever (r^2 - 2r - 15) = 0, the equation is satisfied.
r^2 - 2r - 15 = 0
(r-5)(r+3) = 0
Therefore, r = 5 and r = -3 are also solutions.
Finally, r = 0, r = -3, and r = 5 are the solutions to the original equation.
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