SOLUTION: Terry throws a ball straight up. The initial height of the ball is 3 feet and has an initial velocity of 32 feet per second. The function is modeled by: h(t) = -16t^2 + 32t + 3

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Terry throws a ball straight up. The initial height of the ball is 3 feet and has an initial velocity of 32 feet per second. The function is modeled by: h(t) = -16t^2 + 32t + 3       Log On


   



Question 747356: Terry throws a ball straight up. The initial height of the ball is 3 feet and has an initial velocity of 32 feet per second. The function is modeled by:
h(t) = -16t^2 + 32t + 3
How long is the ball in flight? Round answer to nearest hundredth.
Which formula, process, etc. did you use to solve this problem?

Answer by Alan3354(69443) About Me  (Show Source):
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Terry throws a ball straight up. The initial height of the ball is 3 feet and has an initial velocity of 32 feet per second. The function is modeled by:
h(t) = -16t^2 + 32t + 3
How long is the ball in flight? Round answer to nearest hundredth.
Which formula, process, etc. did you use to solve this problem?
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The equation is a parabola with the vertex at max height.
Find the time at max ht.
Axis of Symmetry is t = -b/2a = -32/-32
t = 1
Find max ht
h(1) = -16 + 32 + 3 = 19 feet.
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Find the time to fall
f(t) = -16t^2 + 19
Find t for f(t) = 0
-16t^2 + 19 = 0
t+=+sqrt%2819%2F16%29
t =~ 1.09 seconds
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Total time in the air = 2.09 seconds