SOLUTION: find value of A, B, C, and D! the quadratic function which takes the value 41 at x=-2 and the value 20 at x=5 and is minimized at x=21 Y=Ax^2

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Question 746893: find value of A, B, C, and D!
the quadratic function which takes the value 41 at x=-2 and the value 20 at x=5 and is minimized at x=21
Y=Ax^2 - Bx + C
the minimum value is D
Answer by MathLover1(20849) (Show Source):
You can put this solution on YOUR website!

if the quadratic function which takes the value at , then

.......eq.1
and if it takes the value at

.......eq.2
and is minimized at

......eq.3

solve the system:

.......eq.1
.......eq.2
......eq.3
_______________________________________
.......eq.1...solve for
......substitute in eq.2a

.......eq.2

.......solve for

.............substitute in eq.2a

........eq.2a

........eq.2b
now use ......eq.3 and substitute and
......eq.3....solve for

now find and

SOLUTION: find value of A, B, C, and D! the quadratic function which takes the value 41 at x=-2 and the value 20 at x=5 and is minimized at x=21 Y=Ax^2 - Bx + C the minimum value is D