SOLUTION: how do you find the vertex and the axis of symetry of: y=-(x+11)^2+8

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Question 74543: how do you find the vertex and the axis of symetry of:
y=-(x+11)^2+8
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
The vertex of the general equation y=a%28x-h%29%5E2%2Bk is (h,k). So h=-11 and k=8 which means the vertex is (-11,8). The axis of symmetry is the vertical line in the form of x=b that passes through the vertex. So the equation is x=-11.