SOLUTION: Graph f(x)=x^2+4x+1 lable the axis of symmerty and vertex! im stuck on this one thanks for the help!

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Graph f(x)=x^2+4x+1 lable the axis of symmerty and vertex! im stuck on this one thanks for the help!      Log On


   



Question 745305: Graph f(x)=x^2+4x+1 lable the axis of symmerty and vertex!
im stuck on this one thanks for the help!

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Graph f(x)=x^2+4x+1 lable the axis of symmerty and vertex!
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Complete the square:
y = x^2 + 4x + ? + 1 - ?
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y = x^2 + 4x + 4 + 1-4
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y = (x+2)^2 -3
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y+3 = (x+2)^2
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Vertex: (-2,-3)
Axis of symmetry: x = -2
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graph%28400%2C400%2C-10%2C10%2C-5%2C10%2Cx%5E2%2B4x%2B1%29
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Cheers,
Stan H.
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