SOLUTION: So I need to write an equation in ax^(2) + bx+ c = y form. I have two ordered pairs and need to get a third ordered pair. The first pair I have is the vertex (2, -5) and passing th

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: So I need to write an equation in ax^(2) + bx+ c = y form. I have two ordered pairs and need to get a third ordered pair. The first pair I have is the vertex (2, -5) and passing th      Log On


   

Question 727204: So I need to write an equation in ax^(2) + bx+ c = y form. I have two ordered pairs and need to get a third ordered pair. The first pair I have is the vertex (2, -5) and passing through (3,1). I am supposed to find a third point through symmetry. I just need the third point and I can solve from here.
Found 2 solutions by jim_thompson5910, lynnlo:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
The x coordinate of the vertex is 2.

The x coordinate of the other point is 3.

So the other point is exactly 1 unit to the right of the vertex.

By symmetry, there will be another point that is exactly 1 unit to the left of the vertex at the same y value (or height) as the point (3, 1)

So subtract 1 from the x coordinate of the vertex (2) to get 2-1 = 1

So this third point is (1,1) since this point is basically reflected over the axis of symmetry x = 2 (so it will have the same height as (3,1))

Answer by lynnlo(4176) About Me  (Show Source):
You can put this solution on YOUR website!
SYMMETRY IS (1,1)