SOLUTION: draw an example of a quadratic equation that has two, one and no solutions.

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Question 727151: draw an example of a quadratic equation that has two, one and no solutions.
Found 2 solutions by jim_thompson5910, MathLover1:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Two solutions (x = -2 or x = 2)



Graph of y+=+x%5E2-4 above

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One solution (x = -5)



Graph of y+=+%28x%2B5%29%5E2 above

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No solutions



Graph of y+=+%28x%2B1%29%5E2%2B4 above

Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!
How to determine the number of solutions.
Let's look at the quadratic formula:
x+=+%28-b+%2B-+sqrt%28b%5E2+-+4ac%29%29%2F2a
The key is the expression in the square root: b%5E2+-+4ac.
In general there are three cases:
  1. b%5E2+-4ac is positive.
    The square root of a positive number is also some positive number.
    So in the numerator of the quadratic formula we will get two values:
    (-b + the square root) and (-b - the square root).
    So when b%5E2+-+4ac+%3E+0 we get two+solutions.
  2. b%5E2+-4ac is zero.
    The square root of zero is zero. So in the numerator we get (-b+%2B+0) and (-b+-+0).
    But both of these are equal to -b!
    So when b%5E2+-+4ac+=+0 we only get one+solution.
  3. b%5E2+-4ac is negative. What is the square root of a negative number? What can we square and get a negative number as an answer? Answer: Nothing.
    You cannot square any Real number and get a negative. So, when b%5E2+-4ac+%3C+0 there are no+solutions.

example:
1.
x%5E2+%2B+8x+-+4+=+0... 8%5E2+-+4%2A1%2A%28-4%29+=+0 which is 64+%2B16+=+80..=> b%5E2+-+4ac+%3E+0; so, we have two+solutions
2.
x%5E2+%2B+4x+%2B+4+=+0... 4%5E2+-+4%2A1%2A%284%29+=+0 which is 16-16+=+0..=> b%5E2+-+4ac+=+0; so, we have one+solution
3.
x%5E2+%2B+4x+%2B+8+=+0... 4%5E2+-+4%2A1%2A%288%29+=+0 which is 16-32+=+-6..=> b%5E2+-+4ac+%3C0; so, we have no+solution