SOLUTION: Is this a quadratic equation? there's only one 'x'. How do i solve this problem? 2(x-3)^2-50=0.

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Is this a quadratic equation? there's only one 'x'. How do i solve this problem? 2(x-3)^2-50=0.       Log On


   

Question 725129: Is this a quadratic equation? there's only one 'x'. How do i solve this problem? 2(x-3)^2-50=0.
Found 2 solutions by Alan3354, josmiceli:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Is this a quadratic equation? there's only one 'x'. How do i solve this problem? 2(x-3)^2-50=0.
------------------
It's a quadratic, the x term (x-3) is squared.
If you expand it you get and x^2 term.
------
The easiest way to solve it is
2(x-3)^2-50=0
2(x-3)^2 = 50
(x-3)^2 = 25
x-3 = 5 --> x = 8
------
x-3 = -5 --> x = -2

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
+2%2A%28+x+-+3+%29%5E2+-+50+=+0+
+2%2A%28+x%5E2+-+6x+%2B+9+%29+-+50+=+0+
+2x%5E2+-+12x+%2B+18+-+50+=+0+
+2x%5E2+-+12x+-+32+=+0+
+x%5E2+-+6x+-+16+=+0+
You can complete the square
+x%5E2+-+6x++=+16+
+x%5E2+-+6x+%2B+%28+-6%2F2%29%5E2+=+16+%2B+%28-6%2F2+%29%5E2+
+x%5E2+-+6x+%2B+9+=+16+%2B+9+
+%28+x+-+3+%29%5E2+=+5%5E2+
+x+-+3+=+5+
+x+=+8+
and, also,
+x+-+3+=+-5+
+x+=+-2+
------------
check answers:
+x+=+8+
+2%2A%28+x+-+3+%29%5E2+-+50+=+0+
+2%2A%28+8+-+3+%29%5E2+-+50+=+0+
+2%2A25+-+50+=+0+
+50+-+50+=+0+
+0+=+0+
and
+x+=+-2+
+2%2A%28+-2+-+3+%29%5E2+-+50+=+0+
+2%2A25+-+50+=+0+
+50+-+50+=+0+
+0=0+
OK