SOLUTION: what is the discriminant in the quadratic equation x2 + 11x + 121 = x + 96

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Question 7210: what is the discriminant in the quadratic equation x2 + 11x + 121 = x + 96
Answer by prince_abubu(198) About Me  (Show Source):
You can put this solution on YOUR website!
The discriminant would be the value of +b%5E2+-+4ac+ if the quadratic equation is written as +ax%5E2+%2B+bx+%2B+c+=+0+.

The equation above isn't quite yet in that form because the right side isn't 0. You'll have to move the terms to the left side and join them with their like terms by addition/subtraction. Once you do that, your equation should now look

+x%5E2+-+10x+%2B+25+=+0+

The a value would be the constant in front of the x^2 term. The b would be the constant in front of the x term, and c is the number standing by itself without variables attached to it. In this example, a = 1, b = -10, and c = 25.

Let's plug those into the b^2 - 4ac formula and see what we'll get:
(-10)^2 - 4*1*25 ---> 100 - 100 = 0. AHA! The discriminant turned out to be 0, which means that your quadratic equation has ONLY 1 solution.