SOLUTION: use the discriminant to determine how many real number solutions the quadratic equation -4j2 + 3j - 28 = 0 has. please and thank you!!!

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Question 7209: use the discriminant to determine how many real number solutions the quadratic equation -4j2 + 3j - 28 = 0 has. please and thank you!!!
Answer by prince_abubu(198) About Me  (Show Source):
You can put this solution on YOUR website!
The discriminant is the formula +b%5E2+-+4ac+. So, where do the a,b, and c come from? It comes from quadratic equation once it's already in the form +ax%5E2+%2B+bx+%2B+c+=+0+.

Your equation +-4j%5E2+%2B+3j+-+28+=+0+ is already in the correct form, so you can readily pull out the a, b, and c. For this one, the a = -4, b = 3, and c = -28. We'll plug those into the discriminant formula and see what kind of value we'll get:

+3%5E2+-+4%28-4%29%28-28%29+=+9+-+448+=+-439+

The discriminant turned out to be a negative number. This means that your quadratic equation has no real number solutions.

IF +b%5E2+-+4ac+%3C+0+, quadratic equation has NO SOLUTION.
IF +b%5E2+-+4ac+=+0+, quadratic equation has EXACTLY 1 SOLUTION.
IF +b%5E2+-+4ac+%3E+0+, quadratic equation has EXACTLY 2 SOLUTIONS.