SOLUTION: solve the quadractic by the square root property (3x-9)^2=12
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Question 717877
:
solve the quadractic by the square root property
(3x-9)^2=12
Answer by
algebrahouse.com(1659)
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(3x - 9)² = 12
3x - 9 = ±√12 {took the square root of each side}
3x = 9 ± √4 √3 {added 9 to each side}
9 ± 2√3
-------- = x {divided each side by 3}
3
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