SOLUTION: 5(x-3)^2+4=7 how would you solve this I have no idea

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Question 717843: 5(x-3)^2+4=7 how would you solve this I have no idea
Found 2 solutions by stanbon, lynnlo:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
5(x-3)^2+4=7
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5(x-3)^2 = 3
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(x-3)^2 = 3/5
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x-3 = sqrt(3/5) or x-3 = -sqrt(3/5)
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x = 3+sqrt(15)/5 or x = 30-sqrt(15)/5
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Cheers,
Stan H.
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Answer by lynnlo(4176) About Me  (Show Source):
You can put this solution on YOUR website!
5(x-3)^2+4=7
5(x-3)^2+4-7=0
5(x-3)^2+3-=0
5(x-3)^2-3=0
5(x-3)^2-3=0
RESULT=============0=0
SOLUTION===========X=3,,,,X=2