SOLUTION: A quadratic equation {{{ ax^2+bx+c=0 }}} has -10 and 5 as solutions. Find the values of b and c if the value of a is 1. Thank in in advance for you help!!

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Question 706871: A quadratic equation +ax%5E2%2Bbx%2Bc=0+ has -10 and 5 as solutions. Find the values of b and c if the value of a is 1.
Thank in in advance for you help!!
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Here is how to begin:

x=-10,
%28-10%29%5E2%2Bb%28-10%29%2Bc=0
100-10b%2Bc=0

x=5,
%285%29%5E2%2B5b%2Bc=0
25%2B5b%2Bc-0

This system is now ready to study:
100-10b+c=0
25+5b+c=0

You might want it in this form:
-10b+c=-100
5b+c=-25

Or better, like this:
10b-c=100
5b%2Bc=-25
Solve this system for b and c.