SOLUTION: if you were given a quadratic relation in the form of: y=a(x-r)(x-s), what can you tell me about the graph relationship:
a) direction of opening
b) location of vertex
c) pattern
Question 706591: if you were given a quadratic relation in the form of: y=a(x-r)(x-s), what can you tell me about the graph relationship:
a) direction of opening
b) location of vertex
c) pattern for y as x increases or decreases by 1 from the vertex
d) X intercepts
e) Y intercepts Answer by josgarithmetic(39617) (Show Source):
You can put this solution on YOUR website! (a) direction of opening:
Depends on the sign of a. If a<0 Then opens downward; if a>0 then opens upward.
(b) location of vertex:
Best to complete the square to put into standard form allowing vertex point to be read directly from the equation. Since we can see or read the roots from the factored equation given, we know that the axis containing the vertex will be in the middle of x=r and x=s.
y=a(x^2-(r+s)x+rs)
Inside the outer parentheses, you want to add , and then outside those parentheses you want to subtract .
.
.
On paper, I find vertex, (,)
(e) Y intercept:
Try let x=0. y=a(0-r)(0-s)=
The y intercept is (0,ars)
(