SOLUTION: Determine the equation of a parabola with vertex (3,9)and an intercept at the origin. Can you show me how you come to the answer? Thank you so much for the help!

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Determine the equation of a parabola with vertex (3,9)and an intercept at the origin. Can you show me how you come to the answer? Thank you so much for the help!      Log On


   

Question 704344: Determine the equation of a parabola with vertex (3,9)and an intercept at the origin. Can you show me how you come to the answer?
Thank you so much for the help!
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Standard form will give a path to finding an equation you want. The vertex corresponds to values you find in the standard form quadratic equation.

y=a%28x-h%29%5E2%2Bk is a way of expressing standard form for a parabola. The vertex is at (h,k). Just fit them in how they belong in the equation from your given vertex point of (3, 9). Because h=3, and k=9, you have y=a%28x-3%29%5E2%2B9.

What's left? You have a point on the graph given as the origin, (0,0). If you fill in h, k, and the coordinates of the origin point, you will be able to solve for the coefficient, a. You SHOULD find that a is less than zero. The vertex is a maximum point of the parabola.