SOLUTION: Can someone please help me with this question:) y=-x^2-2x+2 a)Find the y-intercept...I set x to zero and got (0,2) b)Find the x-intercept (use quadratic formula) Please help:)

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Can someone please help me with this question:) y=-x^2-2x+2 a)Find the y-intercept...I set x to zero and got (0,2) b)Find the x-intercept (use quadratic formula) Please help:)       Log On


   

Question 704148: Can someone please help me with this question:)
y=-x^2-2x+2
a)Find the y-intercept...I set x to zero and got (0,2)
b)Find the x-intercept (use quadratic formula) Please help:)
c)The coordinates of the vertex (no clue)
d)the coordinates of the image of the point corresponding to the y-intercept reflected in the axis of symmetry (really no clue...please help)
Thank you!
Answer by lynnlo(4176) About Me  (Show Source):
You can put this solution on YOUR website!
y intercept=========(0,2)
x intercept=========(-1+√3,0),,,,(-1-√3,0)
vertex==============(-1,3)
axis of sym=========x=-1