SOLUTION: A rocket is launched from atop a 54-foot cliff with an initial velocity of 119 feet per second. The height of the rocket t seconds after launch is given by the equation h = –16t2

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Question 698152: A rocket is launched from atop a 54-foot cliff with an initial velocity of 119 feet per second. The height of the rocket t seconds after launch is given by the equation h = –16t2 + 119t + 54. Graph the equation to find out how long after the rocket is launched it will hit the ground. Estimate your answer to the nearest hundredth of a second.
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Here's the graph of the equation:
+graph%28+600%2C+400%2C+-1%2C+9%2C+-10%2C+280%2C+-16x%5E2+%2B+119x+%2B+54+%29+
The x-axis is in seconds and the y-axis is feet
If you plug in +t+=+7.8+ and then +t+=+7.78+ or +t+=+7.82+
see how close you can get to +h+=+0+ ( hits the ground )