SOLUTION: What is the quadratic equation that has a one root of 1+2i? my work: (1+2i)+(1-2i)= 2 (1+2i)(1-2i)= {{{1-4i^2}}}=1+4=5 a=1 b=-2 c=5 {{{x^2-2x+5}}} I'm not sure if i

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Question 697482: What is the quadratic equation that has a one root of 1+2i?
my work:
(1+2i)+(1-2i)= 2
(1+2i)(1-2i)= 1-4i%5E2=1+4=5
a=1 b=-2 c=5
x%5E2-2x%2B5
I'm not sure if i found the answer correctly.

Found 2 solutions by jim_thompson5910, MathTherapy:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
You have the correct answer. I would have gone a different route, but you did it correctly. Nice work.

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
What is the quadratic equation that has a one root of 1+2i?
my work:
(1+2i)+(1-2i)= 2
(1+2i)(1-2i)= 1-4i%5E2=1+4=5
a=1 b=-2 c=5
x%5E2-2x%2B5
I'm not sure if i found the answer correctly.

That's exactly how the equation is determined.

With a being 1, b = - (sum of roots); and c = product of roots

Now, as these come in congugate pairs, the roots are: (1 + 2i) & (1 - 2i)

Final "product": highlight_green%28x%5E2+-+2x+%2B+5+=+0%29

Good job!!