SOLUTION: A ball is thrown vertically upward with an intial velocity of 96 feet per second. The distance s (in feet) of the ball from the ground after t seconds is s(t) = 96t-16t^2 a. At

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: A ball is thrown vertically upward with an intial velocity of 96 feet per second. The distance s (in feet) of the ball from the ground after t seconds is s(t) = 96t-16t^2 a. At       Log On


   

Question 691577: A ball is thrown vertically upward with an intial velocity of 96 feet per second. The distance s (in feet) of the ball from the ground after t seconds is s(t) = 96t-16t^2
a. At what time will the ball strike the ground?
b. For what time t is the ball more than 128 feet above the ground?
c. When will the ball reach its highest peak? How high is it above the ground?
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
A ball is thrown vertically upward with an intial velocity of 96 feet per second. The distance s (in feet) of the ball from the ground after t seconds is s(t) = 96t-16t^2
a. At what time will the ball strike the ground?
Solve the equation for s(t) = 0.
Ignore the negative solution.
-----------------
b. For what time t is the ball more than 128 feet above the ground?
Solve for the 2 times the eqn = 128.
One time is rising, the later is falling.
---------------
c. When will the ball reach its highest peak? How high is it above the ground?
solve for the vertex of the equation.