SOLUTION: use the quadratic formula for : 4x^2+4=17x my answer: 4x^2+4=17x 4x^2+4-17=0 (-17)^2-4(4)(4)=225 ___ 17(+/-) /225 ___________ = 17(+/-)15 /8 8 r

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: use the quadratic formula for : 4x^2+4=17x my answer: 4x^2+4=17x 4x^2+4-17=0 (-17)^2-4(4)(4)=225 ___ 17(+/-) /225 ___________ = 17(+/-)15 /8 8 r      Log On


   

Question 680795: use the quadratic formula for :
4x^2+4=17x
my answer:
4x^2+4=17x
4x^2+4-17=0
(-17)^2-4(4)(4)=225
___
17(+/-) /225
___________ = 17(+/-)15 /8
8
root: 4, (1/4)
is this right?


Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
yes you are right.
a= 4 b= -17 c= 4

b^2-4ac= 289 - 64
b^2-4ac= 225 sqrt%28%09225%09%29= 15
x=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29
x1=%28-b%2Bsqrt%28b%5E2-4ac%29%29%2F%282a%29
x1=( 17 + 15 )/ 8
x1= 4
x2=( 17 -15 ) / 8
x2= 0.25
(4,0.25)