SOLUTION: u^2+2u-2=0

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Question 669143: u^2+2u-2=0
Found 2 solutions by jim_thompson5910, ReadingBoosters:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Use the quadratic formula to solve for 'u'

u+=+%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29

u+=+%28-%282%29%2B-sqrt%28%282%29%5E2-4%281%29%28-2%29%29%29%2F%282%281%29%29

u+=+%28-2%2B-sqrt%284-%28-8%29%29%29%2F%282%29

u+=+%28-2%2B-sqrt%284%2B8%29%29%2F%282%29

u+=+%28-2%2B-sqrt%2812%29%29%2F2

u+=+%28-2%2Bsqrt%2812%29%29%2F2 or u+=+%28-2-sqrt%2812%29%29%2F2

u+=+%28-2%2B2%2Asqrt%283%29%29%2F2 or u+=+%28-2-2%2Asqrt%283%29%29%2F2

u+=+-1%2Bsqrt%283%29 or u+=+-1-sqrt%283%29

So the exact solutions are u+=+-1%2Bsqrt%283%29 or u+=+-1-sqrt%283%29

Answer by ReadingBoosters(3246) About Me  (Show Source):
You can put this solution on YOUR website!
Complete the square
u%5E2+%2B+2u+-+2+=+0
u%5E2+%2B+2u+%2B+1+=+2+%2B+1
(u+1)(u+1) = 3
sqrt%28u%2B1%29%5E2 = +- sqrt%283%29
u+%2B+1 = +- sqrt%283%29
u+=+-1+%2B-+sqrt%283%29
...
solutions
-1%2Bsqrt%283%29+and+-1+-+sqrt%283%29
.....
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