SOLUTION: Find x-intercept(s)? 0 = 2x^2+4x-48

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Question 668322: Find x-intercept(s)?
0 = 2x^2+4x-48
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
0 = 2x^2+4x-48
To find X intercept y=0
2x%5E2%2B4x-48=0
2%28x%5E2%2B2x-24%29=0
2%28x%5E2%2B6x-4x-24%29=0

2%28x%28x%2B6%29-4%28x%2B6%29%29=0
2%28x%2B6%29%28x-4%29=0
(x+6)(x-4)=0
x=-6 OR x=4
X Intercepts are -6 & 4