Question 641388: The perimeter of a rectangular field is 340m. The length is 13m longer than the width. Find the length and the width.
Please help
Answer by josh_jordan(263)   (Show Source):
You can put this solution on YOUR website! To solve, we need to turn each sentence into an equation. The first sentence says that the perimeter of a rectangular field is 340 meters. The perimeter of a rectangle is twice the length plus twice the height. So, for the first sentence:
2L + 2W = 340
The next sentence says the length is 13 meters longer than the width. In other words,
L = W + 13
So, to find the width, we will substitute L in the first equation with W + 13:
2(W + 13) + 2W = 340
Using the distributive property, multiply 2 by W + 13, which is 2W + 26. Now we have:
2W + 26 + 2W = 340
Combining like terms on the left side of the equal sign gives us:
4W + 26 = 340
Next, subtract 26 from both sides of the equal sign:
4W + 26 - 26 = 340 - 26 =
4W = 314
Finally, divide both sides by 4, which will get W by itself:
This leaves us with our width:
W = 78.5 meters
We know that the length is 13 meters longer than the width, so 78.5 + 13 = 91.5
FINAL ANSWER: Length - 91.5m Width - 78.5m
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