SOLUTION: Solve the following quadratic equation: 4x^2 = 13x + 12

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Question 64085: Solve the following quadratic equation:
4x^2 = 13x + 12
Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
Solve the following quadratic equation:
4x^2 = 13x + 12
4x%5E2-13x-12=13x-13x%2B12-12 set =0
4x%5E2-13x-12=0 factor using your favorite method.
4x%5E2-16x%2B3x-12=0 I'm using the ac or grouping method.
%284x%5E2-16x%29%2B%283x-12%29=0
4x%28x-4%29%2B3%28x-4%29=0
%28x-4%29%284x%2B3%29=0 set each parentheses =0 and solve for x.
x-4=0 or 4x+3=0
x-4+4=0+4 or 4x+3-3=0-3
x=4 or 4x=-3
x=4 or 4x/4=-3/4
x=4 or x=-3/4
Happy Calculating!!!