SOLUTION: for the following equation, state the value of the discriminant and then describe the nature of the solutions 19x^2+3x-15=0

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Question 636842: for the following equation, state the value of the discriminant and then describe the nature of the solutions 19x^2+3x-15=0
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
From 19x%5E2%2B3x-15 we can see that a=19, b=3, and c=-15


D=b%5E2-4ac Start with the discriminant formula.


D=%283%29%5E2-4%2819%29%28-15%29 Plug in a=19, b=3, and c=-15


D=9-4%2819%29%28-15%29 Square 3 to get 9


D=9--1140 Multiply 4%2819%29%28-15%29 to get %2876%29%28-15%29=-1140


D=9%2B1140 Rewrite D=9--1140 as D=9%2B1140


D=1149 Add 9 to 1140 to get 1149


So the discriminant is D=1149


Since the discriminant is greater than zero, this means that there are two real solutions.