SOLUTION: An arrow is shot into the air and its path is modeled by the function h(x) = -4.9t2 + 34.3t - 49 where "h" is the height of the arrow (given in meters) at any given time t (given

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Question 635204: An arrow is shot into the air and its path is modeled by the function h(x) = -4.9t2 + 34.3t - 49 where "h" is the height of the arrow (given in meters) at any given time t (given in seconds). Find the number of seconds necessary for the arrow to reach its maximum height.
Thanks, it means a lot! :)
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

h(x) = -4.9t2 + 34.3t - 49   || Note: 34.3%2F%282%2A4.9%29+=+3.5

h(x)= -4.9(x-3.5)^2 + 60.025 - 49

h%28x%29=+-4.9%28x-3.5%29%5E2+%2B+11.025    V(3.5,11.025)

 Takes 3.5 sec to reach maximum height 0f 11.025m