One of the ways to solve this is to use the quadratic equation. But first, we must identify the a, b, and c values.
A is 2 (because the prerequisite for the first variable to make it a quadratic equation is x^2)
B is -7 (because the prerequisite for the second variable to make it a quadratic equation is x)
C is 6 (because there is no prerequisite for the third variable to make it a quadratic equation)
)(NOTE: A could be x^3 and B could be x^2. All that is required is that it goes from one level of exponents to the next. Squared to a normal x to no x, or maybe Cubed to squared to normal x)
Now we can solve the problem with the quadratic equation.
| Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc) |
Quadratic equation  (in our case  ) has the following solutons:
For these solutions to exist, the discriminant  should not be a negative number.
First, we need to compute the discriminant :  .
Discriminant d=1 is greater than zero. That means that there are two solutions:  .
Quadratic expression  can be factored:
Again, the answer is: 2, 1.5.
Here's your graph:
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