SOLUTION: solve 16x^4+47x^2=3

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Question 633467: solve
16x^4+47x^2=3






Answer by dfrazzetto(283) About Me  (Show Source):
You can put this solution on YOUR website!

16x^4+47x^2=3
16x^4 + 47x^2 - 3 = 0
(16x^2 -1)(x^2 + 3) = 0
16x^2 - 1 = 0; x^2 + 3 = 0
16x^2 = 1; x^2 = -3 (no solution, or radical 3*i, if using complex numbers)
x^2 = 1/16
x = +/- 1/4