SOLUTION: Please help me find values of c so that the equation has 2 real number solution, one-real solution, and no real solution. {{{x^2 - 12x + c = 0}}}.

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Please help me find values of c so that the equation has 2 real number solution, one-real solution, and no real solution. {{{x^2 - 12x + c = 0}}}.      Log On


   

Question 63229This question is from textbook Algebra 2: An Integrated Approach
: Please help me find values of c so that the equation has 2 real number solution, one-real solution, and no real solution.
x%5E2+-+12x+%2B+c+=+0. This question is from textbook Algebra 2: An Integrated Approach

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Please help me find values of c so that the equation has 2 real number solution, one-real solution, and no real solution.
x%5E2+-+12x+%2B+c+=+0.
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Look at the discriminant, as follows:
(-12)^2-4(1)(c)=144-4c
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For 2 real solutions: 144-4c>0; c<36
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For one real solution: 144-4c=0; c=36
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For no real solutions: 144-4c<0; c>36
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Cheers,
Stan H.