SOLUTION: Solve for x/complete the square: 5x^2+2x√10=1?

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Question 630719: Solve for x/complete the square: 5x^2+2x√10=1?
Answer by jsmallt9(3758) About Me  (Show Source):
You can put this solution on YOUR website!
5x%5E2%2B2xsqrt%2810%29=1
First I am going to use the Commutative and Associative Properties on the middle term so that it is something times x, with the x at the end:
5x%5E2%2B%282sqrt%2810%29%29x=1

It is easier to complete a square if the coefficient of the squared term is 1. So we will divide both sides by 5 (or multiply by 1/5):
x%5E2%2B%282sqrt%2810%29%2F5%29x=1%2F5

Next we find half of the middle coefficient. Half of 2sqrt%2810%29%2F5 is sqrt%2810%29%2F5

Next we square the "half" and add that number to both sides. %28sqrt%2810%29%2F5%29%5E2+=+10%2F25+=+2%2F5. Adding 2/5 to each side we get:
x%5E2%2B%282sqrt%2810%29%2F5%29x%2B2%2F5=1%2F5%2B2%2F5
which simplifies to:
x%5E2%2B%282sqrt%2810%29%2F5%29x%2B2%2F5=3%2F5
The left side is a completed square after what we have done. It is (x + the "half" we found earlier) squared:
%28x%2Bsqrt%2810%29%2F5%29%5E2=3%2F5
Now we find the square root of each side:
sqrt%28%28x%2Bsqrt%2810%29%2F5%29%5E2%29=sqrt%283%2F5%29
x%2Bsqrt%2810%29%2F5 = +sqrt%283%2F5%29
Rationalizing the denominator on the right:
x%2Bsqrt%2810%29%2F5 = +sqrt%28%283%2F5%29%285%2F5%29%29
x%2Bsqrt%2810%29%2F5 = +sqrt%2815%2F25%29
x%2Bsqrt%2810%29%2F5 = +sqrt%2815%29%2Fsqrt%2825%29
x%2Bsqrt%2810%29%2F5 = +sqrt%2815%29%2F5
Adding -sqrt%2810%29%2F5 to each side:
x+=+-sqrt%2810%29%2F5+%2B-+sqrt%2815%29%2F5%29
which simplifies to:
x+=+%28-sqrt%2810%29+%2B-+sqrt%2815%29%29%2F5%29