SOLUTION: {{{x(2x^2+9x-56)(3x+10)=0}}} I did this: (2x^3+9x^2-56x)(3x+10)=0 6x^4+27x^3-168x^2+20x^3+90x^2-560x=0 6x^4+47x^3-78x^2-560x=0 6x^3+47x^2-78x-560=0 But I do not know what t

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: {{{x(2x^2+9x-56)(3x+10)=0}}} I did this: (2x^3+9x^2-56x)(3x+10)=0 6x^4+27x^3-168x^2+20x^3+90x^2-560x=0 6x^4+47x^3-78x^2-560x=0 6x^3+47x^2-78x-560=0 But I do not know what t      Log On


   

Question 628978: x%282x%5E2%2B9x-56%29%283x%2B10%29=0
I did this:
(2x^3+9x^2-56x)(3x+10)=0
6x^4+27x^3-168x^2+20x^3+90x^2-560x=0
6x^4+47x^3-78x^2-560x=0
6x^3+47x^2-78x-560=0
But I do not know what to do afterwards (I am supposed to solve for x).
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
x%282x%5E2%2B9x-56%29%283x%2B10%29=0
I did this:
(2x^3+9x^2-56x)(3x+10)=0
6x^4+27x^3-168x^2+20x^3+90x^2-560x=0
6x^4+47x^3-78x^2-560x=0
6x^3+47x^2-78x-560=0
But I do not know what to do afterwards (I am supposed to solve for x).
----------------
Go back to this:
x%282x%5E2%2B9x-56%29%283x%2B10%29=0
x = 0
------
%282x%5E2%2B9x-56%29%283x%2B10%29=0
3x+10 = 0
x = -10/3
==========
%282x%5E2%2B9x-56%29=0
Solve the remaining quadratic.