You can put this solution on YOUR website! Write the following in standard form a+bi
a.) (3-4i)(2+i)
Multiply like any 2 binomials:
= 3(2+i) - 4i*(2+i)
= 6 + 3i - 8i - 4i^2
= 6 - 5i - 4i^2
Then, i^2 = -1
= 6 - 5i -4(-1) = 6 - 5i + 4
= 10 - 5i
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b.) 6-i/1+i
Multiply the NUM and DEN by the conjugate of the DEN, (1-i).
Multiply as in the 1st problem.
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c.) i6+i4+i2+1
Add things up.
If those are supposed to be exponents:
=
= -1 + 1 - 1 + 1
= 0
You can figure out why.
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Use ^ for exponents, Shift 6.