SOLUTION: Given that (x+1) is one of the factors of P(x), then find the rest of the factors of P(x), where {{{P(x)=x^3+6x^2+11x+6}}}

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Question 625287: Given that (x+1) is one of the factors of P(x), then find the rest of the factors of P(x), where
P%28x%29=x%5E3%2B6x%5E2%2B11x%2B6
Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
Given that (x+1) is one of the factors of P(x), then find the rest of the factors of P(x), where
P%28x%29=x%5E3%2B6x%5E2%2B11x%2B6
.
You can either use "long division" OR "synthetic division" to divide:
P%28x%29=x%5E3%2B6x%5E2%2B11x%2B6 by x%2B1
.
Using synthetic division:
-1 | 1 6 11 6
-1 -5 -6
---------------
1 5 6 0
.
quotient:
x^2 + 5x + 6
factoring:
(x+3)(x+2) (the rest of the factors)
.