Question 624896: hi im so confused what happend if come across a problem like this (a+1)(a+2)=0
and a problem n^+3n-12=6 the ^ is 2
Found 3 solutions by Edwin McCravy, ewatrrr, josmiceli:
Answer by Edwin McCravy(20055)   (Show Source):
You can put this solution on YOUR website!
It's called the "zero-factor property", and it is common sense:
The principle is this:
If two quantities are multiplied and their product is 0, then one of
them must be zero:
You have this:
(a+1)(a+2) = 0
This has two quantities (a+1) and (a+2) multiplied together and that
product equals 0. Therefore there are two possibilities:
1. (a+1) is 0
2. (a+2) is 0
Realize that unless one of those equals zero the product would not equal 0.
So to get both possible answers we set each DISABLED_event_one= 0
Setting a+1 = 0, subtracting 1 from both sides gives a = -1
Setting a+2 = 0, subtracting 2 from both sides gives a = -2
Therefore there are two possible solutions a = -1 and a = -2.
---------------------------
nē+3n-12 = 6
Get 0 on the right by adding -6 to both sides:
nē+3n-18 = 0
Factor the left side
(n+6)(n-3) = 0
As above to get both possible answers we set each DISABLED_event_one= 0
Setting n+6 = 0, subtracting 6 from both sides gives n = -6
Setting n-3 = 0, adding 3 to both sides gives n = 3
Therefore there are two possible solutions n = -6 and n = 3.
Edwin
Answer by ewatrrr(24785)  (Show Source):
You can put this solution on YOUR website!
Hi,
If (a+1)(a+2) = 0
Then
(a + 1) = 0
a = -1
or
(a + 2) = 0
a = -2
If (a+1)(a+2) = 0, then a = -1 or a = -2
n^2 + 3n -12 = 6
n^2 + 3n -18 = 0
factoring:
(n + 6)(n - 3) = 0
AND
(n + 6) = 0
or
(n - 3) = 0
n = -6 or n = 3
Answer by josmiceli(19441)  (Show Source):
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