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put this solution on YOUR website!
16a²-56xy+49b²
does not factor.
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However if the xy had been ab, then
16a²-56ab+49b²
would have factored as
(4a-7b)(4a-7b)
(4x-7b)²
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30x³+25x²+5y
factors only by taking out common factor 5
5(6x³+5x²+y)
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However if the y had been an x
30x³+25x²+5x would become
5(6x³+5x²+1) which would become
5(3x+1)(2x+1)
These problems were designed to show you that you have to
be careful to look at the variables.
Edwin