You can put this solution on YOUR website! Using The Pythagorean Theorem
Let a = x, and b = 2x + 4, so that c = 2x + 6.
:
a^2 + b^2 = c^2, therefore:
x^2 + (2x+4)^2 = (2x+6)^2
which is
x^2 + 4x^2 + 16x + 16 = 4x^2 + 24x + 36
combine like terms on the left
x^2 + 4x^2 - 4x^2 + 16x - 24x + 16 - 36 = 0
we have left
x^2 - 8x - 20 = 0
Factors to
(x-10)(x+2) = 0
the positive solution is what we want here
x = 10
:
The threes side of the triangle
a = 10
b = 2(10)+4 = 24
c = 2(10)+6 = 26
:
:
Check this on your calc: enter results: 26
