SOLUTION: 15. Find the x-intercepts. y=x^2-2x+4 x^2-2x+4=0 I then tried to factor however, there are no multiples of four that would equate to two. What am I not doing?

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: 15. Find the x-intercepts. y=x^2-2x+4 x^2-2x+4=0 I then tried to factor however, there are no multiples of four that would equate to two. What am I not doing?      Log On


   

Question 62214: 15. Find the x-intercepts.
y=x^2-2x+4
x^2-2x+4=0
I then tried to factor however, there are no multiples of four that would equate to two. What am I not doing?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
There are no real x-intercepts
If I look for roots by completing the square,
x%5E2+-+2x+%2B+4+=+0
1st, sbtract 4 from both sides
x%5E2+-+2x+=+-4
Now take 1/2 the coefficient of x and square it. add to both sides
x%5E2+-2x+%2B1+=+-4+%2B+1
%28x+-+1%29%5E2+=+-3
Take square root of both sides
x+-+1+=+0+%2B-sqrt%28-3%29
x+=+1+%2B+sqrt%28-3%29 and
x+=+1+-+sqrt%28-3%29
so, the plot does not intercept the x-axis