Question 611390: How would I solve the equation 2t^2+8t-64=0 using the Factoring Method?
I've gotten the problem down to 2(t-4)(x+8) but then sort of crashed...
Answer by jim_thompson5910(35256)   (Show Source):
You can put this solution on YOUR website! If you meant to say 2(t-4)(t+8), then you have the correct factorization.
So 2(t-4)(t+8) = 0, which means that t-4=0 or t+8=0 after we use the zero product property.
So t-4=0 ---> t = 4 or t+8=0 ---> t=-8
This means that the solutions are t = 4 or t = -8
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